mohon pencerahannya kak

garis melalui (0,-2) dan (3, 2)
(y -y₁)/(y₂ -y₁) = (x - x₁)/ (x₂- x₁)
(y + 2) / (2+2) = (x -0) / (3-0)
(y + 2)/ (4)= x /3
3(y + 2) = 4(x)
3y + 6 = 4x
4x - 3y = 6
daerah diarsir mendekati (0,0)
memenuhi 4x- 3y ≤ 6
garis melalui (0,-2) dan (3, 2)
(y -y₁)/(y₂ -y₁) = (x - x₁)/ (x₂- x₁)
(y + 2) / (2+2) = (x -0) / (3-0)
(y + 2)/ (4)= x /3
3(y + 2) = 4(x)
3y + 6 = 4x
4x - 3y = 6
daerah diarsir mendekati (0,0)
memenuhi 4x- 3y ≤ 6